All of these children are more puzzle pieces in the life of Kéri Mihály (Michael Keri).

I’m sharing this chart even though I have not yet found all of the children’s death dates. The highlighted entries will help me explain a thing or two.

The parents listed for the Sára christened in 1842 are Kéri Mihály and Cselei Rebeka (highlighted in blue). I believe the minister made a mistake writing Cselei instead of Nyilas. Here are my reasons:

- I didn’t find a Kéri-Cselei marriage record or any other children for a couple with those names.
- Kéri Mihály and Nyilas Rebeka had a child every two to three years. There would be a five year gap if 1842 Sára is not included in the family.
- The couple had a previous child they named Sára who died in 1841, a year before 1842 Sára was born.
- 1842 Sára’s godparents were also the godparents of five of her siblings. I looked to see if Michael Keri and Rebeka were the godparents for the Sandor Josik and Rebeka Horvat’s children. They weren’t, but Sandor Josik and Rebeka Horvat also were not the godparents for any other couple from 1841 to 1843.

Another mistake was obviously made recording dates for Ester who has some conflicting dates highlighted in red. I double checked all the information when I added it to the chart. If you were to follow the christening record and the death record, Ester was born on the 7th, christened on the 7th, died on the 6th, and buried on the 8th. Her death record also stated that she was 3 days old when she died. Obviously at least one of the dates is not correct.

Life must have been very difficult for Michael and Rebeka Keri. A little baby usually represents much hope for the future. This couple had to witness the deaths of too many of their little ones. My heart goes out to them.

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550 is the product of 10 and the 10th triangular number and is, therefore, the 10th pentagonal pyramidal number.

550 is the hypotenuse of two Pythagorean triples: 330-440-550 and 154-528-550. What is the greatest common factor of each of those triples?

- 550 is a composite number.
- Prime factorization: 550 = 2 x 5 x 5 x 11, which can be written 550 = 2 x (5^2) x 11
- The exponents in the prime factorization are 1, 2, and 1. Adding one to each and multiplying we get (2 + 1)(1 + 1)(1 + 1) = 3 x 2 x 2 = 12. Therefore 550 has exactly 12 factors.
- Factors of 550: 1, 2, 5, 10, 11, 22, 25, 50, 55, 110, 275, 550
- Factor pairs: 550 = 1 x 550, 2 x 275, 5 x 110, 10 x 55, 11 x 50, or 22 x 25
- Taking the factor pair with the largest square number factor, we get √550 = (√25)(√22) = 5√22 ≈ 23.452079

This will keep you busy!

I find it so much fun so it’s a great kind of busy to be!